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Mathematics 8 Online
OpenStudy (anonymous):

Solve the inequality 3(x + 1) + 2(x + 2) > 0. a) x < -7/5 b) x > -7/5 c) x < 7/5 d) x > 7/5

pooja195 (pooja195):

\[\huge~\rm~3(x + 1) + 2(x + 2)\] start by solving this part

pooja195 (pooja195):

\[\huge~\rm~3(x+1)\] distribute

OpenStudy (anonymous):

x > -7/5

pooja195 (pooja195):

Explain your answer

OpenStudy (anonymous):

5x+7>0

pooja195 (pooja195):

That doesn't explain anything .

OpenStudy (anonymous):

Step 1: Simplify both sides of the inequality. 5x+7>0 Step 2: Subtract 7 from both sides. 5x+7−7>0−7 5x>−7 Step 3: Divide both sides by 5. 5x 5 > −7 5 x> −7 5

pooja195 (pooja195):

Neither does that.

OpenStudy (anonymous):

5x/5 > -7/5 x> -7/5

OpenStudy (anonymous):

Step 1: Simplify both sides of the inequality. 5x+7>0

OpenStudy (anonymous):

Step 2: Subtract 7 from both sides. 5x+7−7>0−7 5x>−7

OpenStudy (anonymous):

Step 3:Divide both sides by 5. 5x/5 > -7/5 x> -7/5

OpenStudy (anonymous):

did tha explain all

pooja195 (pooja195):

Well yea but its copied and pasted :P

pooja195 (pooja195):

http://www.mathpapa.com/algebra-calculator.html

OpenStudy (anonymous):

yea i had to make sure my answer right

OpenStudy (anonymous):

cuz im doing the same thing

pooja195 (pooja195):

K

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