Solve the inequality 3(x + 1) + 2(x + 2) > 0.
a) x < -7/5
b) x > -7/5
c) x < 7/5
d) x > 7/5
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pooja195 (pooja195):
\[\huge~\rm~3(x + 1) + 2(x + 2)\]
start by solving this part
pooja195 (pooja195):
\[\huge~\rm~3(x+1)\]
distribute
OpenStudy (anonymous):
x > -7/5
pooja195 (pooja195):
Explain your answer
OpenStudy (anonymous):
5x+7>0
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pooja195 (pooja195):
That doesn't explain anything .
OpenStudy (anonymous):
Step 1: Simplify both sides of the inequality.
5x+7>0
Step 2: Subtract 7 from both sides.
5x+7−7>0−7
5x>−7
Step 3: Divide both sides by 5.
5x
5
>
−7
5
x>
−7
5
pooja195 (pooja195):
Neither does that.
OpenStudy (anonymous):
5x/5 > -7/5
x> -7/5
OpenStudy (anonymous):
Step 1: Simplify both sides of the inequality.
5x+7>0
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OpenStudy (anonymous):
Step 2: Subtract 7 from both sides.
5x+7−7>0−7
5x>−7
OpenStudy (anonymous):
Step 3:Divide both sides by 5. 5x/5 > -7/5
x> -7/5