Rationalize the denominator and simplify.
Hi, welcome to OpenStudy.
thanks
To rationalize the denominator, you must multiply the numerator and denominator by the conjugate of the denominator. What is the conjugate of \(\sqrt{a}-2\sqrt{y}\)?
you would just switch the subtraction to addition right?
how did you make that square root symbol
It's called latex. `\(\sqrt{a}\)` That's the code to do it. You can also use the equation button to do it easier :)
ok cool so wouldnt it be
\[\sqrt{a}+2\sqrt{y}\]
Correct!
So now, lets do the multiplication. \(\Large\frac{\sqrt{a}+2\sqrt{y}}{\sqrt{a}-2\sqrt{y}}\times \frac{\sqrt{a}+2\sqrt{y}}{\sqrt{a}+2\sqrt{y}}=?\)
Hint: \(\sf\Large (x+y)(x+y)=x^2+2xy+y^2\) \(\sf\Large (x+y)(x-y)=x^2-y^2\)
you lost me
Ok, lets multiply the numerators first. \(\sf\Large (\sqrt{a}+2\sqrt{y})\times (\sqrt{a}+2\sqrt{y})=?\)
Use the formula I gave you above.
\[\sqrt{a^2}+4\sqrt{y^2}\]
?
No...
\(\sf\Large (\sqrt{a}+2\sqrt{y})\times (\sqrt{a}+2\sqrt{y})=?\) Use the formula: \(\sf\Large (x+y)\times (x+y)= x^2+2xy+y^2\) remember: x, y, a, and b are all variables.
im lost
@Lyralei can you help me
Where are you lost at?
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