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Mathematics 12 Online
OpenStudy (anonymous):

Rationalize the denominator and simplify.

OpenStudy (anonymous):

OpenStudy (abdullahm):

Hi, welcome to OpenStudy.

OpenStudy (anonymous):

thanks

OpenStudy (abdullahm):

To rationalize the denominator, you must multiply the numerator and denominator by the conjugate of the denominator. What is the conjugate of \(\sqrt{a}-2\sqrt{y}\)?

OpenStudy (anonymous):

you would just switch the subtraction to addition right?

OpenStudy (anonymous):

how did you make that square root symbol

OpenStudy (abdullahm):

It's called latex. `\(\sqrt{a}\)` That's the code to do it. You can also use the equation button to do it easier :)

OpenStudy (anonymous):

ok cool so wouldnt it be

OpenStudy (anonymous):

\[\sqrt{a}+2\sqrt{y}\]

OpenStudy (abdullahm):

Correct!

OpenStudy (abdullahm):

So now, lets do the multiplication. \(\Large\frac{\sqrt{a}+2\sqrt{y}}{\sqrt{a}-2\sqrt{y}}\times \frac{\sqrt{a}+2\sqrt{y}}{\sqrt{a}+2\sqrt{y}}=?\)

OpenStudy (abdullahm):

Hint: \(\sf\Large (x+y)(x+y)=x^2+2xy+y^2\) \(\sf\Large (x+y)(x-y)=x^2-y^2\)

OpenStudy (anonymous):

you lost me

OpenStudy (abdullahm):

Ok, lets multiply the numerators first. \(\sf\Large (\sqrt{a}+2\sqrt{y})\times (\sqrt{a}+2\sqrt{y})=?\)

OpenStudy (abdullahm):

Use the formula I gave you above.

OpenStudy (anonymous):

\[\sqrt{a^2}+4\sqrt{y^2}\]

OpenStudy (anonymous):

?

OpenStudy (abdullahm):

No...

OpenStudy (abdullahm):

\(\sf\Large (\sqrt{a}+2\sqrt{y})\times (\sqrt{a}+2\sqrt{y})=?\) Use the formula: \(\sf\Large (x+y)\times (x+y)= x^2+2xy+y^2\) remember: x, y, a, and b are all variables.

OpenStudy (anonymous):

im lost

OpenStudy (anonymous):

@Lyralei can you help me

OpenStudy (abdullahm):

Where are you lost at?

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