What is the equation of a parabola with a vertex at (0, 0) and a focus at (0, 6).

Question

anonymous · Answer

did you try to make a sketch?

anonymous · Answer

yes but I don't know how to make the equation

anonymous · Answer

is the parabola going to be vertical or horizontal?

anonymous · Answer

vertical?

anonymous · Answer

good. So which of the following equations is used?
(x-h)^2 = 4p(y-k) or (y-k)^2 = 4p(x-h) 

?

anonymous · Answer

I think its the first one but I'm sure

anonymous · Answer

yes it's the first one. If the x is being squared, the it's vertical, and if the y is being squared, it's horizontal. So we have decided that we are going to use

(x-h)^2 = 4p(y-k). All we need to do now is to find the values of h,k, and p yes?

anonymous · Answer

okay. can you tell me how to find them?

anonymous · Answer

What is (h,k) called?