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A wire loop has an area of 0.12 m^2, and the magnetic field through it increases from 0 to 0.20 T in 0.30 s. What is the induced emf in the loop? A. 0.80 V B. 0.080 V C. 0.024 V D. 0.0072 V
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the magnetic flux change is: \[\large \Delta \Phi = \left( {0.2 - 0} \right) \times 0.12 = ...Weber\]
0.024? choice C is our solution?
no, since the magnitude of the requested emf is given by the subsequent formula: \[\large E = \frac{{\Delta \Phi }}{{\Delta t}} = \frac{{0.024}}{{0.3}} = ...volts\]
ohh okay! so now we get 0.08?so it should be choice B is the solution?
yes! correct!
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yay! thank you!!:)
:)
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