Find the y intercepts of \[\large y=\frac{3x^3-x}{x^2-4x}\]
so for the y, intercept, don't you let x = 0 but factor out x 1st \[y = \frac{x(3x^2 - 1)}{x(x - 4)}\]
Am i really allowed to let x = 0 here
3x^2-y(x-4)-1 and putting d>0
well if you factor out x you get \[y=\frac{3x^2 -1}{x - 4}\] and to find the y-intercept for any curve... its a case of letting x = 0 so \[y = \frac{3\times0^2 - 1}{0 - 4}\]
don't we need to worry about the fact that x=0 is not part of the domain
x = 0 would be a point of discontinuity the way I read the question and work on the solution. lol... now I see your point...
Haha mother wolfram also says (0, 1/4) is the y intercept http://www.wolframalpha.com/input/?i=y+intercepts+%283x%5E3-x%29%2F%28x%5E2-4x%29
here is my graph of the equation
It is a point discontinuity, should not be part of the domain
so then the curve doesn't have a y-intercept as its discontinuous at that point
I'm only in high school... so they may do other things at university
Exactly! there should not be any y intercepts for this curve but idk what wolfram is thinking lol
Your graphing calculator is correctly saying (0, 1/4) is a point discont
I'm in Australia and some people, I think from the US seem to not consider a point discontinuity anyway... glad you have a solution
lol this is confusing, I'll just have my teacher explain it to me tomorrow
Yet at the same time wolfram tells us the obvious domain http://www.wolframalpha.com/input/?i=domain+%283x^3-x%29%2F%28x^2-4x%29 Wolfram contradicts itself?
I think after simplifying we can not let \(x=0\) and the graph of the function must be|dw:1434357482874:dw|
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