Question

Simplify 5 log2 k − 8 log2 m + 10 log2 n.

7 log2 (k − m + n)
7 log2 kn over m
log2 50 kn over 8 m
log2 k to the fifth power n to the tenth power over m to the eighth power

Answer 1

@uri @LeAnn01Xxx @e.mccormick @Lady.Liv1776 @TylerMJ325 @Terrorclaw @Phebe @keshaun455 @JoshKoikkara

Answer 2

Hmm...
5*log2 k - 8*log2 m + 10*log2 n

log2 (k^5*n^10)/m^8 , I'm not sure...do u get the same?

Answer 3

I don't want the answer I want to learn how to do it. I'm really bad at Maths ...

Answer 4

quotient rule\[\large\rm log_b y - \log_b x = \log_b \frac{ x }{ y}\]
to condense you can change subtraction to division
product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\]
addition ----> multiplication

power rule \[\large\rm log_b x^y = y \log_b x\]
remember!

Answer 5

@Marcos_RG4L Hmm, I forgot Latex wait.... http://openstudy.com/study#/updates/4ffb5ce1e4b00c7a70c465e9

Answer 6

@Nnesha Hmm...Great !!

Answer 7

first apply power property \[\large\rm log_b x^y = y \log_b x\]

Answer 8

5 log 2 ?

Answer 9

2 is a base
number at front of log became exponent of k