Question

what would be the pressure of a given mass of a gas, if its volume and temperature are doubled ............. ?

Answer 1

Considering an ideal gas, you can use the relation:
\[PV=nRT\]
taking \(n\) (the nomber of molecules) as a constant, since the mass is not changing, and since \(R\) is the ideal gas constant we get:
\[\frac{PV}{T}=constant\]
so if you double the volume and temperature you must get the same constant value for that expression, and then:
\[\frac{P_1V_1}{T_1}=\frac{P_2(2V_1)}{2T_1}\]
what is the relation between the new pressure \(P_2\) and \(P_1\) ??

Answer 2

he wants complement one word

Answer 3

consentration

Answer 4

concentration !

Answer 5

that word is contained in the response to my question:
what is the relation between the new pressure \(P_2\) and \(P_1\) ??
What happens if we cancel out the 2's in the right hand side?

Answer 6

yes concentration