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Mathematics 16 Online
OpenStudy (anonymous):

Help.. A 6-meter pole is supported by guy wires that are anchored to the ground as shown. What is sin D? A) 3/6.71 B) 6.71/6 C) 3/6 D) 6/6.71 Link to question is below 👇👇

OpenStudy (mathstudent55):

Do you know SOHCAHTOA?

OpenStudy (anonymous):

Nope. 😪

OpenStudy (mathstudent55):

SOHCAHTOA is a way to memorize which sides make the ratios of sine, cosine and tangent.

OpenStudy (anonymous):

okay katelyn what is the height

OpenStudy (anonymous):

basically katelyn what im saying sin=b/h

OpenStudy (anonymous):

Whaleee, the height of the triangles sides are both 6.71m I believe. The link I put has the picture of it if you need to refer to it. 👌😄

OpenStudy (mathstudent55):

SOH: \(\sin \theta = \dfrac{opp}{hyp} \) CAH: \(\cos \theta = \dfrac{adj}{hyp} \) TOA: \(\tan \theta = \dfrac{opp}{adj} \) The initials S (sine), C (cosine), T (tangent), O (opposite leg), A (adjacent leg), and H (hypotenuse) are used in the mnemonic above.

OpenStudy (anonymous):

Mhm

OpenStudy (mathstudent55):

You are asked for the sine. Looking above, or remembering the SOH part of SOHCAHTOA, you see that \(\sin \theta = \dfrac{opp}{hyp} \)

OpenStudy (anonymous):

do you know what the answer is?

OpenStudy (anonymous):

Yes, opposite over hypotenuse

OpenStudy (mathstudent55):

Now look at angle D. For angle D, which side is the opposite leg? Which side is the hypotenuse?

OpenStudy (anonymous):

no..

OpenStudy (anonymous):

do you know what the base if a triangle is?

OpenStudy (mathstudent55):

|dw:1434392815161:dw|

OpenStudy (mathstudent55):

|dw:1434392858828:dw|

OpenStudy (anonymous):

Oh crap @mathstudent55 I totally forgot...oh.....ok so I get you

OpenStudy (mathstudent55):

Fill in the blanks: |dw:1434392884772:dw|

OpenStudy (anonymous):

And @bdavis07 uhhh, the base? i think since one side is 3 the other must be 3 so its 6 and @mathstudent55 ok, hold up let me think.....ok 6/6.71 would be sin

OpenStudy (anonymous):

no no no. base is three and the height is 6 so b/h

OpenStudy (anonymous):

base over height

OpenStudy (mathstudent55):

The 3 m base of the small triangle to the left, or the 6 m base of the entire triangle, is not used in this problem. All we need here is the opposite leg and the hypotenuse since the sine ratio is the ratio of the opposite leg to the hypotenuse.

OpenStudy (anonymous):

OKKKKK oh my goodness thank you so much!!! Honestly, I didn't even read it....I was just trying to get the answer fast....maybe I'm to honest...aha...lol thanks. I'm in summer school so this stuff is pretty overwhelming because i've forgotten a lot and i'm not that good at geometry..Thankyou both very much. 😄

OpenStudy (mathstudent55):

|dw:1434393143216:dw|

OpenStudy (anonymous):

6.71 and 3

OpenStudy (mathstudent55):

Don't get overwhelmed. Just study a lot, and ask lots of questions. That's how you learn.

OpenStudy (anonymous):

your welcome katelyn

OpenStudy (anonymous):

Thanks for the advice 😄👌

OpenStudy (mathstudent55):

|dw:1434393288530:dw|

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