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Mathematics 19 Online
OpenStudy (mathmath333):

Functions

OpenStudy (mathmath333):

if \(\large \color{black}{\begin{align} f(x+y,x-y)=xy \hspace{1.5em}\\~\\ \end{align}}\) find \(\large \color{black}{\begin{align} f(x,y)=? \hspace{1.5em}\\~\\ \end{align}}\)

OpenStudy (anonymous):

ok, have you tried it yet?

OpenStudy (mathmath333):

yes

OpenStudy (anonymous):

what did you get?

OpenStudy (mathmath333):

wait

OpenStudy (mathmath333):

i replaced x+y=a , x-y=b and got \(f(a,b)=ax-ab-yx+yb\)

OpenStudy (anonymous):

very good, now eliminate a and b on the RHS

OpenStudy (mathmath333):

how do i eliminate that ?

OpenStudy (anonymous):

sry eliminate x and y, well you can find x and y in terms of a and b

OpenStudy (mathmath333):

i have a question , can i just replace a and b by 'x' and 'y' \(f(a,b)=ax-ab-yx+yb\\ f(x,y)=x^2-xy-yx+y^2=(x-y)^2\)

OpenStudy (anonymous):

emm no, look at to your first substitution

OpenStudy (mathmath333):

ok

OpenStudy (mathmath333):

i got x=(a+b)/2, y=(a-b)/2 is that correct substitution

OpenStudy (anonymous):

that's right, put those back in the f(a,b)

OpenStudy (mathmath333):

got \(f(a,b)=\dfrac{a^2-b^2}{4}\)

OpenStudy (anonymous):

we're done

OpenStudy (mathmath333):

i put now (a,b)-> (x,y) ?

OpenStudy (anonymous):

yes :-)

OpenStudy (mathmath333):

oh thnx

OpenStudy (anonymous):

np math

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