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Mathematics 19 Online
OpenStudy (anonymous):

!!

OpenStudy (freckles):

reaplce a with -1 and b with 2 or vice versa that is you can do either: \[\frac{f(2)-f(-1)}{2-(-1)} \text{ or } \frac{f(-1)-f(2)}{-1-2}\]

OpenStudy (freckles):

now if you want to continue you would need to know the meaning of f(x) like the graph or the expression it is assigned to

OpenStudy (freckles):

impossibly for me to know if that is right or wrong since you still haven't said what f was

OpenStudy (freckles):

ok so f(2)=? look on the x-axis and find x=2 there the find the y value that corresponds to x=2

OpenStudy (freckles):

where is the line at when x=2?

OpenStudy (anonymous):

So, X=2 and Y=0?

OpenStudy (freckles):

yes so f(2)=0

OpenStudy (freckles):

now we need to find f(-1)

OpenStudy (freckles):

where is the line at when x=-1?

OpenStudy (anonymous):

Is that Y=4?

OpenStudy (freckles):

yep so f(-1)=4

OpenStudy (freckles):

now we plug in

OpenStudy (freckles):

\[\frac{f(2)-f(-1)}{2-(-1)}=\frac{0-4}{2-(-1)}\]

OpenStudy (freckles):

0-4=? 2-(-1)=?

OpenStudy (anonymous):

-4/3 ?

OpenStudy (freckles):

yep sounds awesome and it doesn't matter if you did the other way: \[\frac{f(-1)-f(2)}{-1-2}=\frac{4-0}{-1-2}=\frac{4}{-3}=-\frac{4}{3}\] you still get -4/3

OpenStudy (anonymous):

Awesome! Thanks so much for the help!

OpenStudy (freckles):

np

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