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OpenStudy (freckles):
reaplce a with -1 and b with 2
or vice versa
that is you can do either:
\[\frac{f(2)-f(-1)}{2-(-1)} \text{ or } \frac{f(-1)-f(2)}{-1-2}\]
OpenStudy (freckles):
now if you want to continue you would need to know the meaning of f(x)
like the graph or the expression it is assigned to
OpenStudy (freckles):
impossibly for me to know if that is right or wrong since you still haven't said what f was
OpenStudy (freckles):
ok so f(2)=?
look on the x-axis and find x=2 there the find the y value that corresponds to x=2
OpenStudy (freckles):
where is the line at when x=2?
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OpenStudy (anonymous):
So, X=2 and Y=0?
OpenStudy (freckles):
yes so f(2)=0
OpenStudy (freckles):
now we need to find f(-1)
OpenStudy (freckles):
where is the line at when x=-1?
OpenStudy (anonymous):
Is that Y=4?
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OpenStudy (freckles):
yep so f(-1)=4
OpenStudy (freckles):
now we plug in
OpenStudy (freckles):
\[\frac{f(2)-f(-1)}{2-(-1)}=\frac{0-4}{2-(-1)}\]
OpenStudy (freckles):
0-4=?
2-(-1)=?
OpenStudy (anonymous):
-4/3 ?
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OpenStudy (freckles):
yep sounds awesome
and it doesn't matter if you did the other way:
\[\frac{f(-1)-f(2)}{-1-2}=\frac{4-0}{-1-2}=\frac{4}{-3}=-\frac{4}{3}\]
you still get -4/3