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OpenStudy (brucebaner):
OpenStudy (brucebaner):
@Ashleyisakitty
OpenStudy (brucebaner):
@geerky42
OpenStudy (brucebaner):
@10115658
OpenStudy (brucebaner):
plz help me @AkashdeepDeb
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OpenStudy (akashdeepdeb):
I think Bruce Banner would have been able to figure it out by now.
Use, the slant height and the diameter of the cone to find out the height of the cone.
Then, use this height in the volume formula to find the volume.
OpenStudy (brucebaner):
but im not good at this subject
OpenStudy (brucebaner):
@geerky42
OpenStudy (brucebaner):
@TheRaggedyDoctor
OpenStudy (anonymous):
it's a right triangle, find the height with pythagorean
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OpenStudy (anonymous):
man im working on this too and havent gotten to that therom part yet
OpenStudy (anonymous):
|dw:1434410570071:dw|
OpenStudy (anonymous):
how do you find x
OpenStudy (anonymous):
x^2 + 12^2 = 15^2
OpenStudy (anonymous):
x=9
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OpenStudy (anonymous):
so 9 is the height. now plug that into the formula they gave you to find the volume
OpenStudy (brucebaner):
\[9^2+12^2=15^2\] i think?
OpenStudy (anonymous):
huh? you have the radius and the height, plug it into the formula they give you in the question
OpenStudy (brucebaner):
i dont know
OpenStudy (anonymous):
\[V=(1/3)\pi r ^{2}h\]
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OpenStudy (anonymous):
r is 12
h is 9
OpenStudy (anonymous):
plug in those values to get the volume
OpenStudy (brucebaner):
kk
OpenStudy (brucebaner):
\[v=1/3*12^2*9\]
OpenStudy (brucebaner):
right?
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OpenStudy (anonymous):
don't forget pi
OpenStudy (brucebaner):
ik
OpenStudy (brucebaner):
i get 1357.16802635
OpenStudy (brucebaner):
so its B?
OpenStudy (anonymous):
B is your answer
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