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Mathematics 10 Online
OpenStudy (brucebaner):

help me last question plz help me

OpenStudy (brucebaner):

OpenStudy (brucebaner):

@Ashleyisakitty

OpenStudy (brucebaner):

@geerky42

OpenStudy (brucebaner):

@10115658

OpenStudy (brucebaner):

plz help me @AkashdeepDeb

OpenStudy (akashdeepdeb):

I think Bruce Banner would have been able to figure it out by now. Use, the slant height and the diameter of the cone to find out the height of the cone. Then, use this height in the volume formula to find the volume.

OpenStudy (brucebaner):

but im not good at this subject

OpenStudy (brucebaner):

@geerky42

OpenStudy (brucebaner):

@TheRaggedyDoctor

OpenStudy (anonymous):

it's a right triangle, find the height with pythagorean

OpenStudy (anonymous):

man im working on this too and havent gotten to that therom part yet

OpenStudy (anonymous):

|dw:1434410570071:dw|

OpenStudy (anonymous):

how do you find x

OpenStudy (anonymous):

x^2 + 12^2 = 15^2

OpenStudy (anonymous):

x=9

OpenStudy (anonymous):

so 9 is the height. now plug that into the formula they gave you to find the volume

OpenStudy (brucebaner):

\[9^2+12^2=15^2\] i think?

OpenStudy (anonymous):

huh? you have the radius and the height, plug it into the formula they give you in the question

OpenStudy (brucebaner):

i dont know

OpenStudy (anonymous):

\[V=(1/3)\pi r ^{2}h\]

OpenStudy (anonymous):

r is 12 h is 9

OpenStudy (anonymous):

plug in those values to get the volume

OpenStudy (brucebaner):

kk

OpenStudy (brucebaner):

\[v=1/3*12^2*9\]

OpenStudy (brucebaner):

right?

OpenStudy (anonymous):

don't forget pi

OpenStudy (brucebaner):

ik

OpenStudy (brucebaner):

i get 1357.16802635

OpenStudy (brucebaner):

so its B?

OpenStudy (anonymous):

B is your answer

OpenStudy (brucebaner):

thx

OpenStudy (anonymous):

no problem

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