Question

Using the conversion factor from eV (electron volts) to joules, determine which energy line for an electron dropping from one energy level to another would show a line at 435 nm in an emission spectrum. Use the formulas and the energy level information below to answer the question.

Answer 1

Needed constants:

1.00eV = 1.6 * 10^-19 J
c = 3.00 * 10^8 m/s
h = 6.63 * 10^-34 J*s

Energy Level Values:
E6: E= -0.378 eV
E5: E= -0.544 eV
E4: E= -0.850 eV
E3: E= -1.51 eV
E2: E= -3.403V

Answer 2

@chmvijay @wio do you think one of you could help me out on this problem?

Answer 3

@Luigi0210 do you know how to solve this Physics problem?

Answer 4

I don't know physics, sorry.

Answer 5

You know h,c and lamda (435nm)
energy value comes in joules
so use energy and eV conversion value and find the value in eV
that is
1.6 * 10^-19 J =1eV
Energy u got from above= 1eV* 1.6 * 10^-19 J /Energy


did u get it ?

Answer 6

@rosedewittbukater u got it ?

Answer 7

@chmvijay no I'm still pretty lost

Answer 8

E = (3.00 * 10^8 m/s)(6.63 * 10^-34 J*s)/435 nm

Is that it?

Answer 9

I'm really confused and can't figure out what I'm supposed to be doing.

Answer 10

I tried to understand how other people were explaining it and got this:

435 nm = 435 * 10^-9 m

E = (6.63 * 10^-34 J*s) (3.00 * 10^8 m/s)/(435 * 10^-9 m)
E = 4.57 * 10^-19 J

(4.57 * 10^-19 J) (1 eV/1.60 * 10^-19) = 2.86 eV

E5 - E2 = -0.544 - (-3.403) = 2.86 eV

Answer 11

yaa its right indeed RIGHT:)