a proton is moving horizontally at 7.9 * 10^5 m/s. It passes through a vertical magnetic field that points downward. In which direction is teh proton deflected by the magnetic field?
A. to the left of its velocity
B, to the right of its velocity
C. up
D. down
is this using the fourth right hand rule? :/
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OpenStudy (anonymous):
yep
OpenStudy (michele_laino):
|dw:1434438261539:dw|
since the subsequent vector equation holds:
\[\Large {\mathbf{F}} = - e{\mathbf{v}} \times {\mathbf{B}}\]
OpenStudy (anonymous):
ok! what do we plug in? :/
OpenStudy (anonymous):
7.9 * 10^5 m/s
rvc (rvc):
F=qvB
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OpenStudy (michele_laino):
hint:
|dw:1434438414300:dw|
OpenStudy (anonymous):
ohh so it is to the right of its velocity is our solution?
OpenStudy (anonymous):
yep
OpenStudy (michele_laino):
the force is pointing to left with respect to the velocity
OpenStudy (anonymous):
ohh so choice A is the solution?
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OpenStudy (anonymous):
yes
OpenStudy (michele_laino):
that's right!
OpenStudy (michele_laino):
oops..sorry I have supposed it is an electron
OpenStudy (anonymous):
oh so it is to the right? or to the left?
OpenStudy (michele_laino):
so the right answer is to the right
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