Question

What is the value of 19 + 5a^4 – 3b^2 when a = 2 and b = −4?

Answer 1

Hey

what do you think we do first?

Answer 2

hi @jagr2713 :D long time no see

Answer 3

ok we multiply the exponets

Answer 4

right?

Answer 5

correct spo what do we do with the 2^4

Answer 6

Multiply the exponents? Do you mean apply the exponents?

Answer 7

i think????

Answer 8

do you guys have khans academy account?

Answer 9

Yeah, I do. But how is that relevant to the question?

Answer 10

so you can tell me where do i get videos from math n stuff

Answer 11

So we get 16
so we have 19+5*16-3(-4)^2

since the powers of 2 is even, the result will be positive
19+5*16-3*4^2

Now we sumplify 4^2 to 16

19+5*16-3*16

Can you use PEMDAS fro here

Answer 12

256???

Answer 13

...

Answer 14

no we simplify 5*16 to get 80

19+80-3*16

Now 3*16=48

19+80-48

solve from here

Answer 15

\[\large 19~+~(5 \times 16)~-~(3 \times 16)\]

Answer 16

51 (reacts to kid who says 21)

Answer 17

Use PEMDAS

Answer 18

Correct is 51!

Answer 19

thx :D

Answer 20

Glad to had helped today!

Answer 21

https://www.khanacademy.org/computer-programming/starwars-battle-on-the-death-star/5857960179924992 plz vote up to my game