Question

Help with lengths. Thanks!

Answer 1

\[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]

Answer 2

I need to calculate the length of NO. I know how to work these problems EXCEPT I don't know whether to use sin cos or tan.

Answer 3

alright as you can the functions i posted hve 3 variables so
to find NO you should know one angel and one side
so we have to use sin \[\huge\rm sin(60)= \frac{ opposite }{hyp }\]

Answer 4

let NO=x
so x is the opposite side of angle 60 and hyp is 24 so substitute
\[\huge\rm sin(60)= \frac{ x}{24}\]
solve for x :=)

Answer 5

So, in a problem like this, whenever you have the information of one angle and one side you always use sin?

Answer 6

nope it depends on sides and angles
like which angle and side they gave you

Answer 7

for this problem we have to apply sin bec
like i said earlier we need one angle and one side
so given is hyp and angle
and we need to find NO which is opposite side of angle that's why sin

Answer 8

So, sin 60 = .866 * 24 = 20.785

Answer 9

mod should be on degree!!

Answer 10

e*

Answer 11

sin60=root3/2
no need to write before simplifying

Answer 12

yes that's right

Answer 13

i meant no decimal before simplifying :)

Answer 14

My calculator is on degree. I checked. Also, I need to know How to know whether a problem is sin cos or tan?? I want to be able to know right off from looking at the problem which one I need to use.

Answer 15

well
if you have 3 variables formula you should know values of 2 variables to find 3rd one
i need opposite side and given is hyp
so i should apply sin which is equal to opposite over hyp