Question

Help with discrete mathematics please????
Find the 6th term of a geometric sequence with t1 = 7 and t9 = 45,927.

Answer 1

the 6th term hmmm

Answer 2

Ay can some please help me pleaseeee its like no one wants to help me

Answer 3

lol

Answer 4

http://openstudy.com/study#/updates/5580ddbbe4b0e4e582ab20cf

Answer 5

The formula for the nth term of a geometric sequence is
\[t _{n}=t _{1}r ^{n-1}\]
Plug in and solve for r
\[t _{9}=t _{1}r ^{9-1}\]
\[45927=7r ^{8}\]

Answer 6

there is your help :P

Answer 7

Then once you have r, go back and use the same formula to find t6

Answer 8

The formula for the nth term of a geometric sequence is
tn=t1rn−1
Plug in and solve for r
t9=t1r9−1
45927=7r8

Answer 9

lol

Answer 10

cool

Answer 11

byes

Answer 12

R=3 so I got 6237. Is that correct?

Answer 13

r = 3 is right, but not 6237. What did you use for the exponent when finding t6?

Answer 14

\[t _{6}=7\times3^{6-1} \] right?

Answer 15

yes. what did you do next?

Answer 16

\[t _{6}=7\times3^{5}\]

Answer 17

so you should have 7*243

Answer 18

Okay I got 1701 this time

Answer 19

yep, that's it!