Which of the following represents the greatest energy transition from a higher energy level to a lower one? A. emission of a red photon of 770 nm B. emission of a green photon of 550 nm C. emission of a yellow photon of 590 nm D. emission of a blue photon of 450 nm
here we have to compute four energies, namely we have to apply this formula: \[E = \frac{{hc}}{\lambda }\]
ok!
so case red photon: \[E = \frac{{hc}}{\lambda } = \frac{{6.62 \times {{10}^{ - 34}}3 \times {{10}^8}}}{{770 \times {{10}^{ - 9}}}} = ...joules\]
i am confused... what does this mean? 10^-34 3 ?
oops.. sorry: \[E = \frac{{hc}}{\lambda } = \frac{{6.62 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{770 \times {{10}^{ - 9}}}} = ...joules\]
oh! okie! so we get 2.579E-19
that's right!
does that mean choice A is our soluition?
no, we have to to the same computation for other wavelength. case green photon: \[E = \frac{{hc}}{\lambda } = \frac{{6.62 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{550 \times {{10}^{ - 9}}}} = ...joules\]
ok! so we get 3.61E-19
that's right!
case yellow photon: \[E = \frac{{hc}}{\lambda } = \frac{{6.62 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{590 \times {{10}^{ - 9}}}} = ...joules\]
and we get 3.366E-19!
that's right!
finally, case blue photon: \[E = \frac{{hc}}{\lambda } = \frac{{6.62 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{450 \times {{10}^{ - 9}}}} = ...joules\]
4.42E-19!
that's right!
reassuming, we have these subsequent energies: 2.579E-19 J, 3.61E-19 J, 3.366E-19 J, 4.42E-19 J. which is the greatest one?
the last! so our solution is choice D?
oh wait oops sorry it is the first, right? so chocie A is our solution?
I think that 4.42 is greater than 2.579
but it is negative?
E-19? :/
that is an exponential, all our energies have 10^(-19) as exponential
oh so our solution is still choice D?
yes! that's right!
yay! thanks:)
:)
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