Figure DEFG is equivalent to a trapezoid with a semicircle removed from its upper base. What is the area of figure DEFG?
https://www.dropbox.com/s/8gu1yxvuppvea7n/Screenshot%202015-06-16%2023.44.12.png?dl=0
first step: we have to compute the area of trapezoid, which is: \[Area = \frac{{\left( {B + b} \right) \times h}}{2} = \frac{{\left( {14 + 8} \right) \times 5}}{2} = ...c{m^2}\]
55
that's right!
second step: we have to compute the area of the half circle: \[area = \pi \times 4 \times 4 = ...c{m^2}\] please don't multiply by 3.14
XD okay
i got 16
oops.. the area is: \[area = \frac{{\pi \times 4 \times 4}}{2} = ...c{m^2}\]
8
yes! it is 8*pi
B? :D
now the requested area is the subtraction between those areas, namely: \[{\text{requested area}} = {\text{area of trapezoid - area of halfcircle}}\]
hint: \[\begin{gathered} {\text{requested area}} = {\text{area of trapezoid - area of halfcircle = }} \hfill \\ {\text{ = }}55 - 8\pi = ... \hfill \\ \end{gathered} \]
147.58 i think i didnt do it correctly
no, you don't have to multiply by 3.14, the right option is B as you wrote before
but then whhy did u put the pi ;-;
because the area of the half circle is: 8*pi
:I kay.
:)
Thanks. :)
:)
my face
lol ^
thanks for your picture! It is a beautiful gift :)
LOL. Well this time I didn't make it XDDDD but i'm glad you like it.
:)
Now i can sleep :) thank you Z_Z
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