What is ^2√(-125) ?

Question

What is ^2√(-125) ?

anonymous · Answer

$$\sqrt[2]{-125}$$ It looks a little more like this XD

anonymous · Answer

Are you allowed to use complex numbers?

anonymous · Answer

Well i have to be able to write it in decimal form, but i don't
 know if it will be a decimal.

anonymous · Answer

you get me? XD

anonymous · Answer

yes you can write it as
$$ \sqrt {-125} = \a $$

perl · Answer

$$ \sqrt {-125} = \sqrt{-1} \cdot \sqrt{125}= i ~ \sqrt{125}
 
$$

anonymous · Answer

i don't thunk I'm cetching on..

perl · Answer

$$ \sqrt {-125} = \sqrt{-1} \cdot \sqrt{125}= i ~ \sqrt{125}\
= i ~ 11.1803
 
 
$$

anonymous · Answer

Yeah i think thats what the question wants XD

anonymous · Answer

So the answer is 11.1803?

perl · Answer

11.1803i , but it is an approximation

anonymous · Answer

ok thankyou!

anonymous · Answer

oh apperently it has to be a two digget number.. it could be like .12, 1.2, or 12 im not sure XD

perl · Answer

can you take a screenshot of the question, I might have missed something

anonymous · Answer

i cant, im using my computer. But the question just says "What is $$\sqrt[2]{-125}$$ ?"

anonymous · Answer

$$\sqrt[2]{-125}$$  oops i guess it didnt go into equation form

perl · Answer

the simplified exact solution is 
$$ \Large 5 \sqrt 5~ i $$ the approximate solution is $ \large 11.2i $

anonymous · Answer

hm.. so should i just round and say the answer is 11?

perl · Answer

The directions don't say to round though...

anonymous · Answer

no all they ask is for the answer XD

perl · Answer

the exact answer is preferable

anonymous · Answer

yeah but i can only have two numbers.. heh i dont know XD im just going to put 11

anonymous · Answer

do you mind helping me with 1 more?

perl · Answer

ok