Help for a medal???
Charlie needs to simplify the expression below before he substitutes values for x and y. If x ≠ 0 and y ≠ 0, which of the following is a simplified version of the expression below? x^9y^5 x^24y^16 x^6y^3 + x^3y^2 x^15y^8 + x^6y^4
@zepdrix Can you help?
\[\Large\rm \frac{x^{18}y^{12}+x^9y^8}{x^3y^4}\]So um... we have three x's multiplying in the bottom. We'd like to find three x's in the top also, so we can cancel some stuff out. But to do that we need to take the x's out of each term in the top. Do you remember how to factor? :) How do we take three x's out of each term in the top?\[\Large\rm x^{18}y^{12}+x^9y^8=x^3(\quad ?\quad+\quad?\quad)\]
Hannah Bananaaaaa +_+ where you at girrrrrr
Sorry D: Pizza comes first math comes second! Do I add the Xs together?
Ooo pizza noice :U no. You're dividing some x's out of each term.|dw:1434569099407:dw|
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