PLEASE HELP ME UNDERSTAND Solve for x: 3|x − 3| + 2 = 14 No solutions x = −1, x = 8.3 x = 0, x = 7 x = −1, x = 7
First step is to get everything but the absolutes alone. So get everything but \(\left| x-3 \right|\) to the other side.
so subtract 2?
One more after that, but yes.
then divide by 3
Right! So we'll be left with \[\large \left| x-3 \right| = 4\] Now to get the absolutes, you get the negative and positive. So we can split it to look like \[\large x-3=4~~~and~~~x-3=-4\] Now solve them :)
add 3 in both equations, but one equation has no solution right, since the absolute valuse cant be negative?
No the x will be negative, the absolute will cancel it out though :)
ohk?
so x=1 or x=-1
Well plug those two in and see if they work.
they dont
Both, or just one?
just one
poitive 1 doesnt work??
I'll show you what went wrong. \[\large x-3=4\to \large x=4+3\]
ohk
so x=-1 or x=7
Correct! Good job :)
thanks! :)
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