PLEASE HELP ME UNDERSTAND
Solve for x: 3|x − 3| + 2 = 14
No solutions
x = −1, x = 8.3
x = 0, x = 7
x = −1, x = 7
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OpenStudy (anonymous):
First step is to get everything but the absolutes alone. So get everything but \(\left| x-3 \right|\) to the other side.
OpenStudy (anonymous):
so subtract 2?
OpenStudy (anonymous):
One more after that, but yes.
OpenStudy (anonymous):
then divide by 3
OpenStudy (anonymous):
Right! So we'll be left with \[\large \left| x-3 \right| = 4\] Now to get the absolutes, you get the negative and positive. So we can split it to look like \[\large x-3=4~~~and~~~x-3=-4\] Now solve them :)
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OpenStudy (anonymous):
add 3 in both equations, but one equation has no solution right, since the absolute valuse cant be negative?
OpenStudy (anonymous):
No the x will be negative, the absolute will cancel it out though :)
OpenStudy (anonymous):
ohk?
OpenStudy (anonymous):
so x=1 or x=-1
OpenStudy (anonymous):
Well plug those two in and see if they work.
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OpenStudy (anonymous):
they dont
OpenStudy (anonymous):
Both, or just one?
OpenStudy (anonymous):
just one
OpenStudy (anonymous):
poitive 1 doesnt work??
OpenStudy (anonymous):
I'll show you what went wrong. \[\large x-3=4\to \large x=4+3\]
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