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OpenStudy (babynini):
@ganeshie8 you free?
OpenStudy (babynini):
@Empty
OpenStudy (babynini):
@jim_thompson5910
OpenStudy (babynini):
@Nnesha
OpenStudy (babynini):
@freckles
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OpenStudy (babynini):
I've gotten up to
(sinx/cosx )(1/(1-cosx)
OpenStudy (babynini):
@IrishBoy123
rvc (rvc):
@Babynini u here?
rvc (rvc):
you can take the RHS to prove the LHS
it seems easy from right to left
rvc (rvc):
change \(\Large\rm cscx\) to \[\Large\rm \frac{ 1 }{ sinx }\]
and \(\Large\rm secx\) to \(\Large\rm\frac{1}{cos(x)}\)
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OpenStudy (anonymous):
Let's solve for a.
tanx1−cosx=cscx(1+s(2.718282)cx)
Step 1: Multiply both sides by -cosx+1.
antx=−2.718282c4os3x3−c3os2x2+2.718282c3s2x2+c2sx
Step 2: Divide both sides by ntx.
antxntx=−2.718282c4os3x3−c3os2x2+2.718282c3s2x2+c2sxntx
a=−2.718282c4os3x2−c3os2x+2.718282c3s2x+c2snt
Answer:
a=−2.718282c4os3x2−c3os2x+2.718282c3s2x+c2snt