The equation below shows the area of a trapezoid, A, with a height of 9 cm, and one base 35 cm. :
A = 9 over 2(b + 35)
Which of the following formulas correctly solves for the other base, b?
b = 2A over 9 + 35
b = 2 multiplied by A over 9 - 35
b = 2 multiplied by A plus 35, all over 9
b = 2 multiplied by A minus 35, all over 9
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OpenStudy (anonymous):
@zzr0ck3r
OpenStudy (anonymous):
can you help
OpenStudy (anonymous):
@wio
OpenStudy (zzr0ck3r):
\(A=\dfrac{9}{2(b+35)}\) ?
OpenStudy (anonymous):
A=9/2 (b+35)
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OpenStudy (zzr0ck3r):
\[A=\dfrac{9}{2}(b+35)\]?
OpenStudy (anonymous):
Yes
OpenStudy (zzr0ck3r):
multipply both sides by \(\dfrac{2}{9}\) and what do you have?
OpenStudy (zzr0ck3r):
multiply*
OpenStudy (anonymous):
9/2b+ 315/1
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OpenStudy (anonymous):
@skullpatrol
OpenStudy (anonymous):
@wio
OpenStudy (anonymous):
@UsukiDoll
OpenStudy (anonymous):
@freckles
OpenStudy (anonymous):
Hello
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OpenStudy (usukidoll):
so leaving off with what zzrocker said we are solving for b and the last step he did was
\[(\dfrac{2}{9})A=(\dfrac{\cancel{2}}{\cancel{9}})\dfrac{\cancel{9}}{\cancel{2}}(b+35)\\\dfrac{2}{9}A=b+35 \]
OpenStudy (usukidoll):
there's not that much left to do with this problem... if we want b by itself, what do we have to do?
OpenStudy (anonymous):
-35
OpenStudy (anonymous):
from each side
OpenStudy (usukidoll):
yes
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OpenStudy (usukidoll):
\[\frac{2}{9}A - 35 = b\]
that's it :)
OpenStudy (usukidoll):
you're looking for this selection right?
b = 2 multiplied by A over 9 - 35
OpenStudy (anonymous):
thanks @UsukiDoll
OpenStudy (usukidoll):
can I get a medal? :)
OpenStudy (anonymous):
i just did
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