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Will medal and fan!! Find a third-degree polynomial function with integer coefficients that has 2, 7i, and -7i as zeros.
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is it clear that one factor is \((x-2)\)?
if not, then it is now right?
@satellite73 sorry, I forgot to thank you in my thread, so thanks!
the other two factors are \((x-7i)\) and \((x+7i)\) and your job it to multiply this out, which is not as hard as it looks, since \[(x+7i)(x-7i)=x^2+49\]
@NotSephiroth you are welcome!
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@satellite73 thank you so much! I was totally confused by this at first
you got it now right? multiply \[(x-2)(x^2+49)\] and you are done
Yes, I have it from here. Thank you!! You're a life saver!
yw
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