Question

Will medal and fan!!
Find a third-degree polynomial function with integer coefficients that has 2, 7i, and -7i as zeros.

Answer 1

is it clear that one factor is \((x-2)\)?

Answer 2

if not, then it is now right?

Answer 3

@satellite73 sorry, I forgot to thank you in my thread, so thanks!

Answer 4

the other two factors are \((x-7i)\) and \((x+7i)\) and your job it to multiply this out, which is not as hard as it looks, since
\[(x+7i)(x-7i)=x^2+49\]

Answer 5

@NotSephiroth you are welcome!

Answer 6

@satellite73 thank you so much! I was totally confused by this at first

Answer 7

you got it now right? multiply
\[(x-2)(x^2+49)\] and you are done

Answer 8

Yes, I have it from here. Thank you!! You're a life saver!

Answer 9

yw