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Convert polar coordinates (8, 5pi/4) to rectangular coordinates.
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I know r^2 = sqroot (x^2+y^2) but not sure how to do that with this one..
@satellite73
HI!!
you do not have a curve, just a point use \[x=r\cos(\theta), y = r\sin(\theta)\]
oou
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Give me a moment to calculate that :)
so they both equal \[-\frac{ 8\sqrt{2} }{ 2 }\]
which can be simplified to \[-\frac{ 4\sqrt{2} }{ 2 }\] right?
wait..no -4 sqroot2
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