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OpenStudy (anonymous):
Can someone help me with two questions in conic sections.
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OpenStudy (anonymous):
1. What is the equation of the following graph?
OpenStudy (anonymous):
2. What are the foci of the following graph?
OpenStudy (xapproachesinfinity):
i hyperbola has the equation \(\Large \frac{x^2}{a^2}-\frac{y^2}{b^2}=1\)
so you need to find a and b
OpenStudy (anonymous):
how do I find a and b?
OpenStudy (xapproachesinfinity):
you see that box
a is half way from right to left
b is half way from bottom up
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OpenStudy (xapproachesinfinity):
so you just take the length of that rectangle
and divide into half
OpenStudy (xapproachesinfinity):
2b=8 so b=4
2a=6 so a=3
OpenStudy (anonymous):
okay thank you! so the first problem is \[\frac{ x ^{2} }{ 3^{2} }-\frac{ y ^{2} }{ 4^{2} }=1\]
OpenStudy (xapproachesinfinity):
yes !
OpenStudy (anonymous):
Can you also help with the 2nd problem
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OpenStudy (xapproachesinfinity):
to find the foci
you need to find a and b again
then use b^2+c^2=a^2
c=sqrt{a^2-b^2}
c is the distance from the foci
to the center of that rectangle
OpenStudy (xapproachesinfinity):
that will get you the coordinates of the foci
OpenStudy (xapproachesinfinity):
you will find b and a the same way we just did
OpenStudy (anonymous):
I got A=2 and B=5 is that correct?
OpenStudy (xapproachesinfinity):
yes!
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OpenStudy (anonymous):
okay what do I do next?
OpenStudy (xapproachesinfinity):
well i said c is the distance from center to foci
so what do you think any idea
OpenStudy (xapproachesinfinity):
actually an error
\(c=\sqrt{a^2+b^2}=\sqrt{29}\)
the foci has coordinates (0,c)
OpenStudy (anonymous):
so c=5.39?
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