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Mathematics 24 Online
OpenStudy (anonymous):

Can someone help me with two questions in conic sections.

OpenStudy (anonymous):

1. What is the equation of the following graph?

OpenStudy (anonymous):

2. What are the foci of the following graph?

OpenStudy (xapproachesinfinity):

i hyperbola has the equation \(\Large \frac{x^2}{a^2}-\frac{y^2}{b^2}=1\) so you need to find a and b

OpenStudy (anonymous):

how do I find a and b?

OpenStudy (xapproachesinfinity):

you see that box a is half way from right to left b is half way from bottom up

OpenStudy (xapproachesinfinity):

so you just take the length of that rectangle and divide into half

OpenStudy (xapproachesinfinity):

2b=8 so b=4 2a=6 so a=3

OpenStudy (anonymous):

okay thank you! so the first problem is \[\frac{ x ^{2} }{ 3^{2} }-\frac{ y ^{2} }{ 4^{2} }=1\]

OpenStudy (xapproachesinfinity):

yes !

OpenStudy (anonymous):

Can you also help with the 2nd problem

OpenStudy (xapproachesinfinity):

to find the foci you need to find a and b again then use b^2+c^2=a^2 c=sqrt{a^2-b^2} c is the distance from the foci to the center of that rectangle

OpenStudy (xapproachesinfinity):

that will get you the coordinates of the foci

OpenStudy (xapproachesinfinity):

you will find b and a the same way we just did

OpenStudy (anonymous):

I got A=2 and B=5 is that correct?

OpenStudy (xapproachesinfinity):

yes!

OpenStudy (anonymous):

okay what do I do next?

OpenStudy (xapproachesinfinity):

well i said c is the distance from center to foci so what do you think any idea

OpenStudy (xapproachesinfinity):

actually an error \(c=\sqrt{a^2+b^2}=\sqrt{29}\) the foci has coordinates (0,c)

OpenStudy (anonymous):

so c=5.39?

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