FAN AND MEDAL HERE!!!!!!!!!!!!!!!!
Part A: Divide (8x4y3 + 4x3y2 - 2x2y - 12x2y4) by -2x2y. Show your work, and justify each step. (6 points) Part B: How would your answer in Part A be affected if the x2 variable in the denominator was just an x? (2 points) Part C: What is the degree and classification of the polynomial you got in Part A? (2 points)
@only_hanaaa
help me plz!
@mathmate
that is the hardest thing I have ever seen
That's what she said^^
yes but plz help me I will do anything
give me a sec
\[8x^4y^3 + 4x^3y^2 - 2x^2y - 12x^2y^4\]divide each term by \(-2x^2y\)
sorry, my computer just shut off, umm for part b ur need to divide it by x instead of x2
for example \[\frac{8x^4y^3}{-2x^2y}=-4x^2y^2\]
@misty1212
nicely done sattelte
HI!!
do exactly what @satellite73 said divide on term at a time
how do I do that does are big numbers and are confusing
HELP SOMEONE
CAN SOMEONE JUST PLZ HELP US
@mathmath333
oh wow
yeah
IF YOU ARE HERE JUST TO LOOK AT THE CONVERSATION THEN LEAVE IF YOU ARE HERE TO HELP THEN STAY
hi misty
the method is aleady given by sattelite , if u have any doubts regarding exponents see this http://www.mathsisfun.com/algebra/exponent-laws.html
yeah but how am i supposed to divide that on paper or in my head
easier on paper
i can not fiqure the whole thing out. someone plz just give the answer for part a than i can work the rest out
giving anawer is against the rules dude
well can you lead me to the answer
not if u explain it right
what sattelite did came from this \(\large \color{black}{\begin{align} \frac{8x^{\color{red}{4}}y^{\color{blue}{3}}}{-2x^{\color{red}{2}}y^{\color{blue}{1}}}= -4x^{\color{red}{4-2}}y^{\color{blue}{3-1}}=-4x^\color{red}{2}y^\color{blue}{2} \hspace{.33em}\\~\\ \end{align}}\)
is that the answer? :(
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