Question

Graphing a circle. How to figure out the correct integers for the points?!

Answer 1

I always thought the integers were the same

Answer 2

I don't understand how they're positive I thought they would be negative

Answer 3

what are you talking about exactly?

Answer 4

@myininaya I thought the center coordinates for the second would be (-2,-1), but they're positive.. why is that?

Answer 5

x-2=0 when x=2
and
y-1=0 when y=1
so the center is (2,1)

Answer 6

you can do that if confused to compare the equation to
\[(x-h)^2+(y-k)^2=r^2 \text{ where } (h,k) \text{ is center }\]

Answer 7

\[(x-h)^2+(y-k)^2=r^2 \\ (x-2)^2+(y-1)^2=(\sqrt{18})^2\]

Answer 8

@myininaya so just set it equal to zero to get the coordinates?

Answer 9

though you should see when comparing these that 2 is in the place of h
and 1 is in the place of k

Answer 10

yeah if it confused you to compare it to the equation above
but you still need to make sure you have it in the form:
\[(x-h)^2+(y-k)^2=r^2 \]

Answer 11

@myininaya so basically just it equal to zero

Answer 12

oh and that was a 16 not a 18
i have bad eyes

Answer 13

yes if you have it in the form:
\[(x-h)^2+(y-k)^2=r^2\]
then yes

Answer 14

@myininaya ok thx!!!