The width of a rectangle is 12 units. Can the perimeter x of the rectangle can be 60 units when its length y is 18 units? A:No, the rectangle cannot have x = 60 and y = 18 because x + y is less than 60 B:No, the rectangle cannot have x = 60 and y = 18 because x + y is less than 24 C:Yes, the rectangle can have x = 60 and y = 18 because x = 12 + 2y D:Yes, the rectangle can have x = 60 and y = 18 because x = 24 + 2y
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@Mehek14 can you help me please
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so add up 18+18+12+12 to find the perimeter
60
correct so the perimeter can be 60
that means that you can eliminate A and B
ok
now the formula for perimeter is P = 2w + 2l w = width l = length
in your case length is y so P = 2w + 2y
you know that the width is 12 so P = 2(12) + 2y 2*12 = 24
so your formula would be x = 24 + 2y
So D
yes
Can you help with one more
sure
ill open a new question so u can get another medal
alright thanks
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