Find the equation of the circle whose center and radius are given.
center ( 5, 6), radius = 3
This is how it's set up (X___________=_
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OpenStudy (anonymous):
@perl please help
OpenStudy (plasmataco):
(X-5)^2+(Y-6)^2=3^2
OpenStudy (plasmataco):
???
OpenStudy (plasmataco):
Is it correct?
OpenStudy (anonymous):
I don't know. I don't understand how to do this type of problem
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OpenStudy (loser66):
@Plasmataco Please, explain him how to get it. It is better than giving out the free answer.
OpenStudy (loser66):
@Jcameron want to know how to get it?
OpenStudy (anonymous):
Yeah because I don't understand how you got that.
OpenStudy (anonymous):
@Loser66 Yes, or else I don't learn lol
OpenStudy (loser66):
center is (h, k) , so tell me , the given center is (5,6) hence h =?? and k =??
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OpenStudy (anonymous):
H= 5
K=6 ?
OpenStudy (loser66):
yup, and radius =??
OpenStudy (anonymous):
Is 3^2?
OpenStudy (loser66):
nope, just 3, they give you radius =3, how can you get 3^2
OpenStudy (loser66):
ok?
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OpenStudy (anonymous):
Oh sorry, I made a mistake. I was thinking about something different.
OpenStudy (anonymous):
Okay. So, how do I put that into an equation?
OpenStudy (loser66):
\(\color{red}{h =5}\), \(\color{blue}{k=6}\), \(\color {orange}{radius =3}\)
Formula of a circle is
\((x -\color{red}{h})^2+(y-\color{blue}{k})^2=\color{orange}{radius^2}\)
OpenStudy (loser66):
Plug the number in, pppppplease
OpenStudy (anonymous):
(x-5)^2+(y-6)^2=3^2 ?
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