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Iron-59 has a half-life of 45.1 days. How old is an iron nail if the Fe-59 content is 25% that of a new sample of iron? Show all calculations leading to a solution. 25=100 e^(-.693 t/45.1) Ln(25)=ln(100) -.693 t/45.1 ln(25)-ln(100)=-.693 t/45.1 ln(25/100)=-.693t/45.1 t= - 45.1/.693 ( ln .25) t=90.2 days.
@Luigi0210 @dan815 @nincompoop @aaronq
@Miracrown @zepdrix @mathmate
it's good \(\checkmark\)
Is there anything else I need to do? @aaronq
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nope
Yey. Awesome. Thank you!
no probs, good job!
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