Question

Find the standard form of the equation of the parabola with a focus at (0, -10) and a directrix at y = 10. (5 points)

y = -1/10x2
y =-1/40 x2
y2 = -40x
y2 = -10x

Answer 1

did you make a sketch?

Answer 2

no... @sourwing

Answer 3

perhaps you should make a sketch now?

Answer 4

how??

Answer 5

@sourwing

Answer 6

there is a blue [draw] button below. Click that and draw

Answer 7

i don't know how to draw.

Answer 8

@sourwing

Answer 9

the general equation for a parabole whose focus is:
F=(0, p/2)
and whose directrix is:
y= -p/2, is:
\[\Large {x^2} = 2py\]
now, using your data we have:
\[\Large \frac{p}{2} = - 10\]
so, what is p=...?
then substitute that value of p, into my equation above, so you will get your answer

Answer 10

parabola*

Answer 11

-5 !!!! @Michele_Laino