Question

could someone help me create an equation from this proabola
http://learn.flvs.net/webdav/educator_algebraII_v14/module06/images/06_05_assessment/06_05_06_01.gif

Answer 1

Same

Answer 2

that what the link was

Answer 3

standard or vertex?

Answer 4

i think standard

Answer 5

it might not actually matter which one

Answer 6

ice what does that even say

Answer 7

ahh okay O.o

Answer 8

You need the equation of a parabola, the vertex location (x,y)=(h,k) and one point where the parabola crosses the x-axis.

The equation:

$$
y=a(x-h)^2+k
$$

The Vertex:

(h,k) is your vertex, you can get that from your plot, it is the top-most point.
h represents how for left or right you need to move the vertex and k represents how far up or down it is

The x-intercept:

Next, to find a you need to set y=0, set x equal to the point where the parabola crosses the x-axis. Solve for a.

Put it all together:

Once you have a,h and k, put back into the equation above and you will have y as a function of x, your equation of a parabola that models your graph.

That's it!

Note that a should be negative because the parabola goes more and more negative when x gets more and more positive.