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Mathematics 12 Online
OpenStudy (anonymous):

Robert bought 2 different candles. the ratio of short candle to the longer candle is 5 : 7. it is known that the longer candle when lighted can melt in 3.5 hours while the shorter candle when lighted can melt in 5 hours. now the two candles are lighted at the same time. after how many hours will the length of two candles be exactly equal ?

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

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OpenStudy (anonymous):

i sure the shrter one is more fat :)

ganeshie8 (ganeshie8):

Haha is the answer 2 hours ?

OpenStudy (anonymous):

im asking this problem, so i dont know the answer. can you show how to get that ?

ganeshie8 (ganeshie8):

Easy... Let \(5x\) = length of the short candle in meters \(7x\) = length of the longer candle in meters \(t\) = time elapsed in hours after the candles are lit

ganeshie8 (ganeshie8):

rate of melting of short candle = \(\large \frac{5x ~\text{meters}}{5 \text{hours}} = x\text{ meters/hour}\) starting length of short candle = \(5x\) The length short candle after \(t\) hours is given by \[5x-x*t \tag{1}\]

ganeshie8 (ganeshie8):

rate of melting of long candle = \(\large \frac{7x ~\text{meters}}{3.5 \text{hours}} = 2x\text{ meters/hour}\) starting length of short candle = \(7x\) The length longer candle after \(t\) hours is given by \[7x-2x*t \tag{2}\]

ganeshie8 (ganeshie8):

set both equation equal to each other and solve \(t\)

OpenStudy (anonymous):

ok got it... thanks for your help

ganeshie8 (ganeshie8):

weird, the time at which the candles get to same heights doesn't depend on their starting lengths

OpenStudy (dan815):

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