Question

MEDAL!!
ALGEBRA 2
19. l-4b-8l+l-1-b^2l +2b^3;b=2

Answer 1

\[\left| -4(2) - 8 \right| + \left| -1-(2)^2 \right| + 2(2)^3 \]

Answer 2

You are basically solving the above ^
Since they've told you that " b = 2" , this means that you just sub (plug) in 2 where the "b" is.
Basically REPLACE all the "b's" with 2 and solve :)

BUT you want to take note of the absolute value sign also...

Answer 3

So firstly, let's simplify the parts inside the first absolute sign " -4(2) - 8 "
What does -4(2) - 8 = ?

Answer 4

-8 - 8

Answer 5

-16?

Answer 6

yes :) Now can you see how that part was BETWEEN the absolute value sign?
Absolute value means you always take the POSITIVE of that value inside.
So \[\left| -4(2) - 8 \right| = \left| -8-8 \right|= \left| -16 \right| = 16 \]

Answer 7

\[\left| -1-(2)^2 \right| = ? \]

Answer 8

-5

Answer 9

remember, you take the "absolute value" of -5...
So \[\left| -1-(2)^2 \right| = \left| -5 \right| = 5 \]

And now solve the last part:
\[2(2)^3 = ? \]

Answer 10

32

Answer 11

i mean 24

Answer 12

not quite.
What does \[2^3 = ? \]

Answer 13

16

Answer 14

err nope.. \[2^3 = 2\times2\times2 = ? \]

Answer 15

8

Answer 16

yes and we wanted:
\[2(2)^3 = 2\times2\times2\times2 = ?\]

Answer 17

2(16)

Answer 18

2(2)^3 = 2 times 2 times 2 times 2 = 16

Answer 19

2^3=8

Answer 20

So now we solved the three parts of this equation : \[\left| -4(2) -8 \right| + \left| -1-(2)^2 \right| + 2(2)^3 \]
\[= 16 + 5 + 16 = ? \]

Answer 21

37

Answer 22

correcttt

Answer 23

final answer is 37??

Answer 24

yes

Answer 25

thankyou zoo much

Answer 26

you're welcome :)