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Solve this quadratic equation using the quadratic formula. 2x2 - 10x + 7 = 0
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\[\frac{ -10\sqrt{-10^{2}-4(2)(7)} }{ 2(2) }\]
is this right?
Almost...
The quadratic formula is \(\sf\LARGE x=\frac{ -b\pm \sqrt{b^2-4ac}}{2a}\) where the equation is: \(\sf\Large ax^2+bx+c=0\)
Remember, your b is negative and we are doing -B in the first part. So you should get \(\sf -(-10)\)
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\[\frac{ 10\pm \sqrt{-10^{2}-4(2)(7)} }{ 2(2) }\] so like that maybe
correct
but just remember it's \(\sf (-10)^2\) not \(\sf -(10^2)\)
ok thanks :)
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