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Mathematics 18 Online
OpenStudy (anonymous):

A circle is centered at (−3, 2) and has a radius of 2. Which of the following is the equation for this circle? (x + 3)2 + (y − 2)2 = 2 (x − 3)2 + (y + 2)2 = 4 (x + 3)2 + (y − 2)2 = 4 (x − 3)2 + (y + 2)2 = 2

OpenStudy (anonymous):

Equation of a circle is \[\large (x-h)^{2}~+~(y-k)^{2}=r^{2}\] \[\large (h,k)~=~Center~coordinates~of~circle\] \[\large r~=~radius\] Plug in the h,k, and r, and tell me what you get :)

OpenStudy (anonymous):

so would r= 2 and then h and k would be (-3,2)? just wondering

OpenStudy (anonymous):

Right, those are all what you would plug in.

OpenStudy (anonymous):

oh ok (: one second

OpenStudy (jdoe0001):

as aforementioned \(\bf (x-{\color{brown}{ h}})^2+(y-{\color{blue}{ k}})^2={\color{purple}{ r}}^2 \qquad center\ ({\color{brown}{ -3}},{\color{blue}{ 2}})\qquad radius={\color{purple}{ 2}}\)

OpenStudy (anonymous):

|dw:1435103502827:dw| is this right ?

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