Probability
Which parts are you having trouble with? For example can you do section 1 of the question?
Im having ahard time analyzing 2,4 and 6..
oh and even 5
Hmm. @kropot72 . The first condition was a' u c.. what does it mean?
Looking at part 1 \[\large A'\cup C\] means the union of the complement of subset A and subset C.
so the answer would be {3,4,5} right?
Not really. The complement of A, denoted by A' is the set of elements which belong to S but do not belong to A. Can you try find A' as a first step in solving part 1 and post your result.
Your calculation does not have the complement of A, which the question writes as A'. My previous posting explained the meaning of the complement of A. Please refer to it.
S = {1, 2, 3, 4, 5, 6, 7, 8, 9} A = {2, 4, 7, 9} A' = {?, ?, ?, ?, ?}
1,3,,5,6,8,
Oh sorry. The condition was a' u c not s. =)
As you posted, A' = {1, 3, 5, 6, 8} Now what is the union of A' and C?
3,4,5 right?
But what if.. the condition was like this? [a' u c]'.. is it a null set?
Not really. You need to find the union of A' = {1, 3, 5, 6, 8} and C = {2, 3, 4, 5}.
The union of A' and C is the set of all those elements, each one of which belongs to A' or to C, or belongs to both A' and C.
so its 1,2,3,4
Why have you not included 5, 6 and 8?
5 is in A' and C. 6 and 8 are both in C.
Ah yes. Im sorry. Im still digesting this complement thing
How about no. 3? |dw:1435210474368:dw|
np. So we have \[\large A'\cup C={1, 2, 3, 4, 5, 6, 8}\]
With curly brackets at the start and end of the elements.
=)
Ahm. Ill try to answer the no. 3 condition..
is it 1,7,9?
\[\large B\cap C'\] means the intersection of B and the complement of C'. The intersection is the set of all elements common to both B and C'.
the intersection would be 3,5
Yes {1, 7, 9} is correct for section 3.
Sorry, I must log out for a while to eat. Perhaps I can continue later. Hope I have been of some help.
Sure thing @kropot72 Thank you thank you so much =)
You're welcome :)
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