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OpenStudy (anonymous):
\[-np - 80 < 60\]
OpenStudy (anonymous):
What do you think we would do first?
OpenStudy (anonymous):
add 80 to both sides
OpenStudy (anonymous):
Yep! Which we then get \[-np < 140\]
OpenStudy (anonymous):
So now we want to get the 'n' by itself right?
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OpenStudy (anonymous):
divide by -n
OpenStudy (anonymous):
Well that is one way but there is a faster/ easier way to doing this. Try thinking of the problem like this: \[-1np\] We are able to divide the -1 to remove the negative on the 'np' side.
OpenStudy (anonymous):
so what is the answer
OpenStudy (anonymous):
and can u help me with another one
OpenStudy (anonymous):
\[np > 140\] Now because we divide by a negative, making us flip the sign.
So the answer, if you were looking just for 'n', would be \[n > \frac{ 140 }{ p }\]
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OpenStudy (anonymous):
Sure
OpenStudy (anonymous):
Solve 2a − 5d = 30 for d.
OpenStudy (anonymous):
Hmmm... I remember this type of equation specifically, however, I do not remember the way in which you were to solve it. I will try my best though.
OpenStudy (anonymous):
ok thank u
OpenStudy (anonymous):
But I think the answer would either be d = -6 or d = -3
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