Question

medal
What is an equation of the line, in point-slope form, that passes through the given points and has the given slope?
pont:(8,-8);slope:3
y-8=3(x+8)
y+8=3(x+8)
y-8=3(x-8)
y+8=3(x-8)

Answer 1

this one easier than the last, since they gave you the slope to being with

Answer 2

\[y-y_1=m(x-x_1)\] with
\[x_1=8,y_1=-8\] remember the sign comes with the number

Answer 3

you got it yet?

Answer 4

ok so a is the answer

Answer 5

no
are you getting the x's confused with the y's?

Answer 6

i think so

Answer 7

i can see it is a bit confusing because they use the point \((8,-8)\)
plug in \(x\) for \(x_1\) and \(-8\) for \(y_1\) in
\[y-y_1=m(x-x_1)\]

Answer 8

oops i meant "plug in \(8\) for \(x\)"

Answer 9

remember that x comes before y in the alphabet, just like it does in \((x,y)\)
course you have to sing that whole song until the end

Answer 10

ok im los t

Answer 11

ok lets go slow

Answer 12

the "point slope" formula for a line, with slope \(m\) and point \((x_1,y_1)\) is
\[\huge y-y_1=m(x-x_1)\]

Answer 13

\(x\) and \(y\) are variables, they stay in the answer \(x_1\) and \(y_1\) are numbers

Answer 14

you have in this case
\[x_1=8,y_1=-8,m=3\] so we plug them directly in to the formula, remembering that the minus sign that is in front of the number stays there

Answer 15

i will plug them directly in :\[y-(-8)=3(x-8)\]

Answer 16

then you see that \(-(-8)=+8\) so in the end you get
\[y+8=3(x-8)\]

Answer 17

now i see thanks