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Will fan and medal. Find the value of x in the logarithm log2 x = -3. A. 1/3 B. 3/2 C. 1/8 D. 8
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\[\log_2(x)=3\] Apply the log identity \[\log_b(x) = y \iff x= b^y\]
Could you please just walk me through the steps because I really don;t know what I'm doing.
don't forget the minus sign *\(\log_2(x)=-3\)
there only is two steps, the first is to apply the log identity
\[\log_2(x)=-3\] raising both sides of the equation to the base of the logarithm... \[2^{\log_2(x)}=2^{-3}\] the left hand side simplifies \[x=2^{-3}\]
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now jus simplify the right hand side
would it be 1/8?
yep
Thank you!
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