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Mathematics 24 Online
OpenStudy (mindblast3r):

help pls

OpenStudy (anonymous):

with?

OpenStudy (mindblast3r):

\[r^2=\frac{ 9 }{ 2 }\]

OpenStudy (mindblast3r):

\[r=\frac{ 3\sqrt{2} }{ 2 }\]

OpenStudy (mindblast3r):

how does the \[\frac{ 9 }{ 2 }\]

OpenStudy (mindblast3r):

turn into \[\frac{ 3\sqrt{2} }{ 2 }\]

OpenStudy (anonymous):

because 3 goes into 9 2 times so 2 is the square root of 3 and 9 and then the denominator stays the same

Parth (parthkohli):

\[r^2 = \frac{9}{2}\]\[\Rightarrow r^2 = 9 \cdot \frac{1}{2}\]\[\Rightarrow r = \sqrt 9 \cdot \sqrt{\frac{1}{2}}\]\[\Rightarrow r = 3 \cdot \frac{1}{\sqrt2}= 3 \cdot \frac{\sqrt 2}{\sqrt 2 \cdot \sqrt 2} = \frac{3\sqrt 2}{2}\]

OpenStudy (anonymous):

at least thats what i get out of it thats what it looks like to me

OpenStudy (mindblast3r):

oh!!! I get it now! Thank you soo much!! I've been stuck on that forever!

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