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OpenStudy (anonymous):
@ganeshie8 @uri
OpenStudy (anonymous):
The temperature of a chemical reaction ranges between 30°C and 70°C. The temperature is at its lowest point when t = 0 and completes one cycle over a six-hour period. What is a sine function that would model this reaction?
OpenStudy (anonymous):
@Preetha @SolomonZelman
OpenStudy (anonymous):
OH and here are the answers:
f(t) = 20 sin 10t + 50
f(t) = 50 sin 10t + 20
f(t) = 50 sin π/5 t + 20
f(t) = 20 sin π/5 t + 50
OpenStudy (xapproachesinfinity):
oh you have answer choices good!
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OpenStudy (xapproachesinfinity):
hmm i see the period has to be in radians
OpenStudy (anonymous):
Yesss
OpenStudy (xapproachesinfinity):
i would of think that the lowest degree is 30
but they give you 20 as the lowest somehow!
OpenStudy (xapproachesinfinity):
so A and D are not good options since t=0 give 50 which is not lowest degree as claimed!
OpenStudy (xapproachesinfinity):
you would have to convert 6 hour into radions to see what is could be
each hour is 2pi radians
hmm but then this does not give us what we wanted
12pi is no good
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OpenStudy (anonymous):
Here's a sample problem similar to it, if that'll help.
OpenStudy (anonymous):
@undeadknight26 @sleepyjess
OpenStudy (anonymous):
@SolomonZelman
OpenStudy (xapproachesinfinity):
ok let's see
at t=6
we have f(6)=70
50sin(6B)+20=70
sin(6b)=1
6b=pi/2
b=pi/12
didn't get that pi/5 there