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Mathematics 10 Online
OpenStudy (anonymous):

Help with functions?

OpenStudy (anonymous):

@ganeshie8 @uri

OpenStudy (anonymous):

The temperature of a chemical reaction ranges between 30°C and 70°C. The temperature is at its lowest point when t = 0 and completes one cycle over a six-hour period. What is a sine function that would model this reaction?

OpenStudy (anonymous):

@Preetha @SolomonZelman

OpenStudy (anonymous):

OH and here are the answers: f(t) = 20 sin 10t + 50 f(t) = 50 sin 10t + 20 f(t) = 50 sin π/5 t + 20 f(t) = 20 sin π/5 t + 50

OpenStudy (xapproachesinfinity):

oh you have answer choices good!

OpenStudy (xapproachesinfinity):

hmm i see the period has to be in radians

OpenStudy (anonymous):

Yesss

OpenStudy (xapproachesinfinity):

i would of think that the lowest degree is 30 but they give you 20 as the lowest somehow!

OpenStudy (xapproachesinfinity):

so A and D are not good options since t=0 give 50 which is not lowest degree as claimed!

OpenStudy (xapproachesinfinity):

you would have to convert 6 hour into radions to see what is could be each hour is 2pi radians hmm but then this does not give us what we wanted 12pi is no good

OpenStudy (anonymous):

Here's a sample problem similar to it, if that'll help.

OpenStudy (anonymous):

@undeadknight26 @sleepyjess

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (xapproachesinfinity):

ok let's see at t=6 we have f(6)=70 50sin(6B)+20=70 sin(6b)=1 6b=pi/2 b=pi/12 didn't get that pi/5 there

OpenStudy (anonymous):

Okay..

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