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Chemistry 15 Online
OpenStudy (vera_ewing):

chem

OpenStudy (vera_ewing):

OpenStudy (vera_ewing):

@rvc

rvc (rvc):

i dont know this i havent revised :(

OpenStudy (vera_ewing):

@Hoslos

OpenStudy (sweetburger):

Im thinking [x]/[.25][.25]=3.0x10^-3 which becomes x=.003x.0625=.00019 which is equivalent to 1.9x10^-4M being the concentration of Fe3+. If you are wondering why there is only one x in the numerator it is because the Ag is a solid and therefore falls out of the equation.

OpenStudy (anonymous):

Use Kc= (concentration of product1^mol * concetration of product2^mol)/(concentration of reactant1^mol * concentration of reactant 2^mol) Also, take note that Kc works for Aqueous substances only.

OpenStudy (vera_ewing):

@Hoslos So the answer is A?

OpenStudy (anonymous):

Making substitutions, we get 3*10^-3= (Fe3+)^1/(0.25^1 * 0.25^1) Fe3+= 0.625* (3*10^-3)= 1.875*10^-3 or A.

OpenStudy (vera_ewing):

Thank you!

OpenStudy (anonymous):

Fe3+= 0.0625 * 0.003= 1.875*10^-4 or A.

OpenStudy (sweetburger):

Looks good :)

OpenStudy (anonymous):

Yes, was because of the mistake in the significant figures.

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