Pure water is neutral. What is the appropriate justification for this?
Choice A, neutral means the H+ ions equal the OH- ions, giving a pH of 7. The first choice is pretty much that exact definition
@Teddyiswhatshecallsme where is choice A from?
Yes, pure water is neutral because we have an equal concentration of \[H _{3}O ^{+} \] and \[OH ^{-}\] ions. In fact water only very slightly ionizes, so \[K _{w}\] value is very very small\[= - 1 \times10^{-14}\] Finding the equilibrium expression of water gives us \[Kw = [OH ^{-}][H3O ^{+}]\] That is for the reaction: \[H _{2}O + H _{2} O \leftarrow \rightarrow H _{3}O ^{+} + OH ^{-}\] And \[Kw = 1 \times 10 ^{-14}\] And \[[OH ^{-}] = [H _{3} O ^{+}]\] \[= 1 \times 10^{-7}\] Finding pH= \[-\log ([H _{3} O ^{+}] )\]= \[-\log( 1 \times 10^{-7}) = 7\] 7 pH is neutral.
Just A. lolol
Multiple choice.
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