Write the equation of the quadratic function with roots -2 and 4 and a vertex at (1, 9).
the vertex form of a quadratic is a(x - h)^2 + k where the vertex is at (h,k)
so in your case we have f(x) = a(x - 1)^2 + 9
now you need to find the value of a which you can do using the given roots
so what is a?
a is a number to be found
the roots are -2 and 4 so points of intersection on x-axis are (-2,0) and (4,0) So plugging these values into the above equation and solving for a will give you the final equation
I'm really not good at this. but i think i'm kinda getting it? could you just show me please?
ok f(x) = 0 when a - -2 so 0 = a(-2-1)^2 + 9 0 = 9a + 9 -9a = 9 a = -1 so we;ve found a
so the answer is f(x) = -1(x - 1)^2 + 9?
yes
thanks so much. i will fan and medal you. :)
they might want it in standard form though just expand and simplify
yw ty
they haven't asked for that so leaving in in the above form should be ok
yep, that should be fine. thanks again.
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