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Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x. f(x) = x2 - 3 and g(x) = square root of quantity three plus x
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f(g(x)) means substitute f(x) for the x in f(x) \[f(g(x)) = (\sqrt{3+x})^2-3\] do the reverse to get g(f(x)) \[g(f(x))=\sqrt{3+(x^2-3)}\] Simplify them both. If you get "x" for both the functions are inverses
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