Question

\[100^x=0^+\]

Answer 1

\[100^x=0^+ ~~\iff~~x=\log_{100}0^{+}=-\infty\]

Answer 2

\[x = \lim_{y\to-\infty}y\]

Answer 3

i think we can avoid the limits by moving to extended reals

Answer 4

but
\[100^x=0 \quad\implies\quad x=-\infty\]

Answer 5

Nope, I see what you did there.
identically equal to 0 and tens to 0 from positive side are two different things

Answer 6

*tends

Answer 7

right

Answer 8

At any rate below should be fine

\[100^x= 0^{+}\quad\implies\quad x=-\infty\]

if \(0^{+}\) is defined as getting close to 0 from right hand side, but honestly i never worked wid these operators... so i think "+ on top right corner" operation needs to be defined first.

Answer 9

\[100^x= 0^{+}\quad\implies\quad x=-\infty^+\]

Answer 10

what does that even mean xD