Question

find df/dx and df/dy :

Answer 1

\[\sqrt{4x ^{2} + 3y ^{2}}\]

Answer 2

first simplify this a bit
= [ (4x^2 + 3y^2)^½]^3
= (4x^2 + 3y^2)^(3/2)

Answer 3

now you use the chain rule

Answer 4

oh!! or is this partial differentiation??

Answer 5

wait, sorry, the derivatives are to be solved separately. like dx first then dy haha sorry

Answer 6

cause i saw that you should treat y as a constant etc etc for dx and vice versa for dy...

Answer 7

yes - oh - its been a long time i'm struggling to remember this stuff...

Answer 8

haha, im just studying it right now and already struggling. lol. so, am i right?

Answer 9

yes - you have the general idea but i'm a bit hazy on it to be honest

Answer 10

im just wondering if y is to be constant, so finding dx would just be sqrt(4x^2) dx ?

Answer 11

the radical is confusing me i might get it wrong

Answer 12

i'm sure some of the other guys will be more familiar with it than i am.

Answer 13

well chage the radical to an exponent as i have done

Answer 14

1/2 right?

Answer 15

ok i think i got it from here. haha. thanks!

Answer 16

square root = ^(½) yes

Answer 17

yw