Question

When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed?

2 Al + 6HCl → 2 AlCl3 + 3 H2

Answer 1

@dan815

Answer 2

@abb0t

Answer 3

Please help guys

Answer 4

I know I need to balance the equation first.

Answer 5

6Al + 18HCl -> 6AlCl3 + 9H2

Answer 6

It was already balanced to begin with

Answer 7

ok so how do i find limiting reactant and # of moles of H2 that can be formed

Answer 8

You find the limiting reagent by finding which ever one needs the least amount of moles to produce your product. Keeping in mind that your coefficients need to be taken into account